(2y^+5y-9)=(-3y+7)

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Solution for (2y^+5y-9)=(-3y+7) equation: 



(2y^+5y-9)=(-3y+7)

We move all terms to the left:

(2y^+5y-9)-((-3y+7))=0

We get rid of parentheses

2y^+5y-((-3y+7))-9=0



We calculate terms in parentheses: -((-3y+7)), so:

(-3y+7)

We get rid of parentheses

-3y+7

Back to the equation:

-(-3y+7)



We add all the numbers together, and all the variables

7y-(-3y+7)-9=0

We get rid of parentheses

7y+3y-7-9=0

We add all the numbers together, and all the variables

10y-16=0

We move all terms containing y to the left, all other terms to the right

10y=16

y=16/10

y=1+3/5

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